May 11, 2006 | May 10 | May 12 | 2006 | FOTD Home |
Fractal
visionaries
and enthusiasts:
How could one rate a regular pentagon? They could not. A
pentagon is unratable. All regular pentagons are similar.
They're all the same. Therefore I gave today's image, which
features a blatantly obvious pentagon, no rating. True, the
pentagon is decorated by flowery petals, but it is still a pentagon.
The parent fractal was created by combining small portions of Z^(-0.5)
and Z^(-1.5) then adding (1/C). It consists of several oversized
arcs floating in empty space. Today's scene is located in the
smaller arc, which has by far the most detail.
When I examined this smaller arc, I found no signs of Mandelbrot
midgets, but hey, there's nothing wrong with the pentagons that I did
find, a great example of which appears in today's picture.
The passes=b option works exceptionally well with today's image, and it
is quite amusing when the outline of the perfect pentagon is suddenly
traced out.
The weather was perfect here at Old Fractal Central on Wednesday; the
fractal cats were perfect also. My day was appropriately
busy. The next FOTD is scheduled to appear in 24 hours. It
actually might do so. Until then, take care, and if you actually
did find the theory of everything, it would still be nothing but a
theory.
Jim Muth
jamth@mindspring.com
jimmuth@aol.com
START PARAMETER FILE=======================================
FOTD_for_11-05-06 { ; time=0:02:53.89--SF5 on a P200
reset=2004 type=formula formulafile=allinone.frm
formulaname=MandelbrotMix4 function=recip passes=b
center-mag=-4.18371/-13.9732/62.87884/1/-3.1/8.018\
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LFLLHKKJIKLHJNGJPEIRDI000 }
frm:MandelbrotMix4 {; Jim Muth
a=real(p1), b=imag(p1), d=real(p2), f=imag(p2),
g=1/f, h=1/d, j=1/(f-b), z=(-a*b*g*h)^j,
k=real(p3)+1, l=imag(p3)+100, c=fn1(pixel):
z=k*((a*(z^b))+(d*(z^f)))+c,
|z| < l }
END PARAMETER FILE=========================================